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The molal cryoscopic for water is 1.86 "...

The molal cryoscopic for water is `1.86 "K mol"^(-1)`. When 3.42 g of sugar ( molar mass = 342) is dissolved in 100 g of water, the solution will freeze at

A

`-1.86^(@)C`

B

`1.86^(@)`

C

`-3.92^(@)C`

D

`2.42^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaT_(f)=(1000 xx K_(f) xx W)/(Mw)`
=`(1000 xx 1.86 xx 342)/(100 xx 342)=1.86`
`:. T_(f) =0-1.86=-1.86^(@)C`
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