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Osmotic pressure of 40% (wt.//vol.) urea...

Osmotic pressure of `40%` (wt.`//`vol.) urea solution is `1.64 atm` and that of `3.42%` (wt.`//`vol.) cane sugar is `2.46 atm`. When equal volumes of the above two solutions are mixed, the osmotic pressure of the resulting solution is:

A

`1.64 atm`

B

`2.46 atm`

C

`4.10 atm`

D

`2.05 atm`

Text Solution

Verified by Experts

The correct Answer is:
D
`pi=(pi_(1) + pi_(2))/2`, if equal volumes are mixed,volume of solution becomes double.
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