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Dry air was passed successively through ...

Dry air was passed successively through a solution of 5 gm of solute dissolved in 80.0 gm of water and through pure water. The loss in weight of the solution was 2.5 gm and that of the pure solvent was 0.04 gm. What is the molecular weight of the solute?

A

31.25

B

3.125

C

312.5

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
`P^(@)-P_(S) prop ` loss in weight of water chamber.
and `P_(S) prop ` loss in weight of solution chamber.
`(P^(@)-P_(S))/-P_(S) = n_(2)/n_(1) =(W_(2) xx Mw_(1))/(Mw_(2) xx W_(1))`
or `0.04/2.50 = (5 xx 18)/(Mw_(2) xx 180)`
`:. Mw_(2) =31.25`
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