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An aqueous solution freezes at -0.186^...

An aqueous solution freezes at
`-0.186^(@)C (K_(f)=1.86^(@)` ,`K_(b)=0.512^(@)`. What is the elevation in boiling point?

A

0.186

B

0.512

C

`0.512/1.86`

D

0.0512

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaT_(b) = K_(b) xx Molality`
`DeltaT_(f) = K_(f) xx Molality`
`:. (DeltaT_(b))/(DeltaT_(f))=K_(b)/K_(f) rArr (DeltaT_(b)) =(DeltaT_(f) xx DeltaT_(b))/DeltaT_(f) =(0.186 xx 0.512)/1.86`
`=0.0512`
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