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The vapour pressure of a solvent decreas...

The vapour pressure of a solvent decreased by `10 mm` of `Hg` when a non-volatile solute was added to the solvent. The mole fraction of solute is `0.2`, what would be the mole fraction of solvent if the decrease in vapour pressure is `20 mm` of `Hg`.

A

0.8

B

0.6

C

0.4

D

0.2

Text Solution

Verified by Experts

The correct Answer is:
C
`:. P^(@) - P_(S) = P^(@) xx "Mole fraction of solute" `
`10 = P^(@) xx 0.2`
`20 = P^(@) xx chi_(2)`
`:. chi_(2) = 0.4 rArr chi_(1) ("solvent") = 1-0.4 =0.6`
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