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Total Vapour pressure of mixture of 1mol...

Total Vapour pressure of mixture of 1mol A`(p_(A)^(0)=150 "torr")`and 2mol B `(p_(B)^(0)=240 "torr")`is `200 "torr"`. In this case

A

There is positive deviation from Raoult's law.

B

There is negative deviation from Raoult's law.

C

There is no deviation from Raoult's law.

D

Molecular masses of `A` and `B` are also required.

Text Solution

Verified by Experts

The correct Answer is:
B
`P_("total")=P_(A)^(@) + P_(B)^(@)`
= `210 mm gt 200 mm`
Vapour pressure is decreased.
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