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lowering of vapour pressure due to a sol...

lowering of vapour pressure due to a solute in `1` molal aqueous solution at `100^(@)C` is
a.`13.44 mm Hg` ,b. `14.14 mm Hg` ,c.`13.2 mm Hg` ,d. `35.2 mm Hg`

A

13.44 torr

B

14.12 torr

C

312 torr

D

352 torr

Text Solution

Verified by Experts

The correct Answer is:
A
`(DeltaP)/P^(@) =(W_(2) xx Mw_(2))/(Mw_(2) xx W_(1))`
`DeltaP=(1 xx 18)/(1000) xx 760 =13.68`
(at `100^(@)C`,`VP=760 "torr"`)
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