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The relative decreases in the vapour pre...

The relative decreases in the vapour pressure of an aqueous solution containing `2 mol [Cu(NH_(3))_(3)Cl]Cl` in `3 mol H_(2)O` is `0.50`. On reaction with `AgNO_(3)`, this solution will form

A

`1 mol AgCl`

B

`0.25 mol AgCl`

C

`2 mol AgCl`

D

`0.40 mol AgCl`

Text Solution

Verified by Experts

The correct Answer is:
A
`(DeltaP)/P^(@)=0.50 = (n_(1)i)/(n_(1)i + n_(2))`
`0.50 =(2i)/(2i + 3)`
`i=1.5 = 1 + x`
`x=0.5`
Hence,2 mol NaCl will exists as `1 "mol" Cl^(ө)` due to `50%` ionization.
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