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Mixture of volatile components A and B h...

Mixture of volatile components A and B has a total vapour pressure (in torr)p=`254-119 x_(A)`is where`x_(A)`mole fraction of A in mixture .Hence`P_(A)^@`and `P_(B)^@`are(in torr)

A

`254,119`

B

`119,254`

C

`135,254`

D

`154,119`

Text Solution

Verified by Experts

The correct Answer is:
C
`P_(Total)= P_(A)^(@)chi_(A) + P_(B)^(@)chi_(B)`
`= P_(A)^(@)chi_(A) + P_(B)^(@)(1-chi_(B))`
`P_(B)^(@) - (P_(B)^(@)-P_(A)^(@))chi_(A)`
Given equation =`254-119chi_(A)`
Compare with the given equation,
`:. P_(B)^(@) = 254`,`P_(B)^(@)-P_(A)^(@)=119`
`:. P_(A)^(@)=254-119=135`
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