Home
Class 12
CHEMISTRY
The osmotic pressure of a solution conta...

The osmotic pressure of a solution containing `40 g` of solute `("molecular mass 246")` per litre at `27^(@)C` is `(R=0.0822 atm L mol^(-1))`

A

`3.0 atm`

B

`4.0 atm`

C

`2.0 atm`

D

`1.0 atm`

Text Solution

Verified by Experts

The correct Answer is:
B
`pi=CRT=((W_(2)/(Mw_(2)))RT)/V`
Given`W_(2)=40 g`
`Mw_(2) = 246`
`T=27^(@)C = 300 K`
`V= 1 L`
Substituting all the values , we get
`pi=(40/246 )xx 0.082 xx 300 =4 atm`
Promotional Banner

Similar Questions

Explore conceptually related problems

The osmotic pressure of a solution containing 0.1 mol of solute per litre at 273 K is

The normality of a solution containing 60 g of CH_3COOH per litre is

The osmotic pressure of a solution of 3.42 g sugar (molar mass 342) in 500 mL at 300 K will be

The osmotic pressure of a solution containing 5 g of substance (molar mass =100) in 308 m L of solution was found to be 4.0 atm at 300 K . Calculate the value of solution constant (R)

Calculate the osmotic pressure of a solution containing 0.02 mol of NaCl and 0.03 mol of glucose in 500 mL at 27^(@)C .

The osmotic pressure of a solution at 273 K is 2.5 atm. The osmotic pressure of the same solution at 273^(@)C is :

The molality of a solution containing 0.1 mol of a substance in 100g of water is :

Osmotic pressure of solution (density is 1 g/ml) containing 3g of glucose(molecular weight=180 g) in 60 g of water at 15^(@)C is