Home
Class 12
CHEMISTRY
In the depression of freezing point expe...

In the depression of freezing point experiment, it is found that the:

A

The vapour pressure of the solution is less than that of pure solvent.

B

The vapour pressure of the solution is more than that of pure solvent.

C

Only solute molecules solidify at freezing point.

D

Only solvent molecules solidify at freezing point.

Text Solution

Verified by Experts

The correct Answer is:
A, D
In the depression in freezing point experiment, it is found that the vapour pressure of a solution is less than that of pure solvent. Only solvent molecules solidify at freezing point. The temperature at which the vapour pressure of the liquid is equal to the vapour pressure of the solid is graphically the temperature at which the vapour pressure curve of the solid. When a non-volatile solute is dissolved in a liquid, its freezing point is lowered.
Promotional Banner

Similar Questions

Explore conceptually related problems

Expain the depression in freezing point of solution.

1575.2 g of C_(6)H_(5)OH (phenol) is dissolved in 960 g of a solvent of solvent of K_(f)=14 K kg mol^(-1) . If the depression in freezing point is 7 K , then find the percentage of phenol that dimerizes.

In an experiment, 72.5 g of C_(6)H_(5)OH (phenol) is dissolved in a solvent of K_(f)=14 . If the depression in freezing point is 7 K , find the percentage of phenol that dimerizes.

MX_(2) dissociates into M^(2+) and X^(ө) ion in an aqueous solution, with a degree of dissociation (alpha) of 0.5 . The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in absence of ionic dissociation is

Given that DeltaT_(f) is the depression in freezing point of the solvent in a solution of a non-volatile solute of molarity m ,the quantity underset(m rarr0)(Lt) (DeltaT_(f)//m) is equal to ……………. .

The depression in freezing point is maximum if the solvent used is

Assertion (A): Larger the value of cryoscopic constant of the solvent, lesser will be the freezing point of the solution. Reason (R ): Depression in the freezing point depends on the nature of the solvent.

During depression of freezing point in a solution, the following are in equilibrium: