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When 0.004 M Na(2)SO(4) is an isotonic a...

When `0.004 M Na_(2)SO_(4)` is an isotonic acid with `0.01 M `glucose, the degree of dissociation of `Na_(2)SO_(4)` is

A

`75%`

B

`50%`

C

`25%`

D

`85%`

Text Solution

Verified by Experts

The correct Answer is:
A
For `Na_(2)SO_(4)`,`pi_(1)=iMRT`
`=ixx 0.004 xx RT`
For glucose,`pi_(2)=CRT`
`=0.01 RT`
`pi_(1) =pi_(2)`(isotonic)
or `0.004i =0.01`
`i=2.5`
Total particles =`1-alpha + 2alpha +alpha`
`1+2alpha`
`:.i=(1 + 2alpha)/1=2.5`
`alpha=0.75` or `75%` dissociated.
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