Home
Class 12
CHEMISTRY
The EMF of a galvanic cell composed of t...

The `EMF` of a galvanic cell composed of two hydrogen electrodes is `177 mV`. If the solution at one of the electrode has `[H^(o+)]=10^(-3)`, find the `[H^(o+)]` at the other electrode.

Text Solution

Verified by Experts

`H_(2)|H^(o+)(10^(-3))|H_(2)^(o+)(x)|H_(2)`
`E=-0.059(pH_(1)-pH_(2))=-0.059(3-pH_(2))`
`177xx10^(-3)V=-0.177+pH_(2)xx0.059`
`pH_(2)=(0.354)/(0.059)=6`
`[H^(o+)]=10^(-6)M`
Promotional Banner

Similar Questions

Explore conceptually related problems

The hydrogen electrode is dipped in a solution of pH=3 at 25^@ C. What is the potential of the electrode?

In a standard hydrogen electrode , the concentration of H^(+) is :

The e.m.f. of a cell is 1.3 V. The positive electrode has a potential of 0.5 V. The potential of negative electrode is :

One mole of hydrogen peroxide (H_2O_2) has a mass same as that of

The emf of a galvanic cell constituded with the electrodes Zn^(2+)//Zn (-0.76V) and Fe^(2+)//Fe (-0.41V) is

Write half cell reaction and E^o Value of (SHE) standard hydrogen electrode.

The emf of a galvanic cell constituted with the electrodes Zn^(2+)"|"Zn(-0.76V) and Fe^(2+)"|"Fe(-0.41V) is :

The hydrogen electrode is dipped in a solution of pH 3 at 25^@C . The potential of the cell would be (2.303 RT//F = 0.059V) :

The oxidation potential of hydrogen electrode H_(2)"|"H_(3)O^(+)(aq) will be greater than zero if