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The standard EMF of a galvanic cell invo...

The standard `EMF` of a galvanic cell involving cell reaction with `n=2` is found to be `0.295 V` at `25^(@)C` . The equilibrium constant of the reaction would be

A

`4.0 xx 10^(12)`

B

`1.0xx10^(2)`

C

`1.0 xx 10^(10)`

D

`2.0xx10^(11)`

Text Solution

Verified by Experts

The correct Answer is:
c
`log K_(eq)=(n_(cell)E^(c-)._(cell))/(0.059)=(2xx0.295)/(0.059)=10`
`:. K_(eq)=10^(10)`
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