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The pH of LHE in the following cell is :...

The `pH` of `LHE` in the following cell is `:`
`Pt, H_(2)(1atm)|H^(o+)(x M)||H^(o+)(0.1M)|H_(2)(0.1atm)Pt` E_(cell)=0.295V`.

A

`6.5`

B

`6.0`

C

`5.5`

D

`4.0`

Text Solution

Verified by Experts

The correct Answer is:
c
`E_(cell)=[0.059(pH_(a)-pH_(c)+(1)/(2)log.((p_(H_(2)))_(a))/((p_(H_(2)))_(c))]`
`=0.059[pH_(a)+log(0.1)+(1)/(2)log .((1)/(0.1))]=0.295`
`pH_(a)=5.5`
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