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wedge^(@).(eq) of BaCl(2), H(2)SO(4), an...

`wedge^(@)._(eq)` of `BaCl_(2), H_(2)SO_(4)`, and `HCl(aq)` solutions are `x_(1), x_(2),` and `x_(3),` respectviley . `wedge^(@)._(eq(BaSO_(4)))` is `:`

A

`x_(1)+x_(2)-x_(3)`

B

`x_(1)-x_(2)-x_(3)`

C

`x_(1)+x_(2)-2x_(3)`

D

`x_(1)-2x_(2)+x_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`wedge^(@)._(eq(BaCl_(2)))=lambda^(@)._(eq(Ba^(2+)))+lambda^(@)._(eq(Cl^(c-))),`
`wedge^(@)._(eq(H_(2)SO_(4)))=lambda^(@)._(eq(H^(o+)))+lambda^(@)._(eq(SO_(4)^(2-))),`
`wedge^(@)._(eq(HCl))=lambda^(@)._(eq(H^(o+)))+lambda^(@)._(eq(Cl^(c-)))`
Thus, `wedge^(@)._(eq(BaSO_(4)))=wedge^(@)._(eq(BaCl_(2)))+wedge^(@)._(eq(H_(2)SO_(4)))-wedge^(@)._(eq(HCl)),`
`=x_(1)+x_(2)-x_(3)`
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