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A conductivity cell is used to measure t...

A conductivity cell is used to measure the conductance of electrolyte . It makes use of conductivity of water which does not contain any ions. The cell constant of conductivity cell is determined.
If the cell constant is `0.40 cm^(-1)`, the conductivity of `0.051 M NaCl` solution having `R=1850 ohm` is equal to

A

`1.08xx10^(-4)S cm^(-1)`

B

`4.32 xx 10^(-4) S cm^(-1)`

C

`2.16xx10^(-4) S cm^(-1)`

D

`5.04xx10^(-5) S cm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
c
Use `:k=GxxG^(**)=(0.4)/(1850)=2.16xx10^(-4)S cm^(-1)`
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