If same quantity of electricity is passed through three electrolytic cells containing `FeSO_(4),Fe_(2)(SO_(4))_(3)`, and `Fe(NO_(3))_(3)`, then

Options

A. The amount of iron deposited in `FeSO_(4)` and `Fe_(2)(SO_(4))_(3)` are equal.
B. The amount of iron deposited in `FeSO_(4)` is `1.5` times of the amount of iron deposited in `Fe(NO_(3))_(3)`
C. The amount of iron deposited in `Fe_(2)(SO_(4)_(3)` and `Fe(NO_(3))_(2)` are equal.
D. The same amount of gas is evolved in all three cases of the anode.

Answer

b,c,d

Explanation

`FeSO_(4): Fe^(2+)+2e^(-) rarr Fe" "1F-=(1)/(2)molFe`
`Fe(NO_(3))_(3): Fe^(3+)+3e^(-) rarr Fe" "1F-=(1)/(3) mol Fe`
`Fe_(2)(SO_(3))_(3):Fe^(3+)+3e^(-) rarr Feimplies 1F-=(1)/(3) mol Fe` ltbtgt Amount of `Fe` deposited in `Fe(NO_(3))_(3)=` Amount of `Fe` deposited in `Fe_(2)(SO_(4))_(3)`.
Amount of `Fe` deposited in `Fe_(2)(SO_(4))_(3)=(1)/(2):(1)/(3)=1.5:1`
At anode `:4overset(c-)(O)H rarr O_(2)+2H_(3)O+4e^(-)`
In all cases same amount of gas is evolved at the anode.