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13.5 g of Al get deposited when electr...

13.5 g of Al get deposited when electricity is passed through solution of `AlCl_3` . The number of faradays used are

A

`0.5`

B

`1.0`

C

`1.5`

D

`2.0`

Text Solution

Verified by Experts

The correct Answer is:
c
`Al^(3+)+3e^(-)rarr Al`
`1 mol of Al =27g =3F`
`:. 13.5g of Al=(3)/(27)xx13.5-=1.5F`.
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