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A solution of 9.65A flowing for 10 mi n ...

A solution of `9.65A` flowing for `10 mi n` deposits `3.0g` of the metal which is monovalent. The atomic mass of the metal is

A

10

B

50

C

30

D

`96.5`

Text Solution

Verified by Experts

The correct Answer is:
b
Let `A` be the atomic weight of metal.
`1 mol` of metal `=Ag`
`96500CimpliesAg`
`9.65xx10xx60implies(A)/(96500)xx9.65xx10xx60`
`:. Axx0.06=3g`
`A=(3)/(0.06)=50`
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