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500mL of 1N solution of CuCl(2) was elec...

`500mL` of `1N` solution of `CuCl_(2)` was electrolyszed with a current fo 2 amperes for 1 hour. What is the normality of the remaining `CuCl_(2)` solution ?

A

`0.85`

B

`0.15`

C

`0.30`

D

`1.0`

Text Solution

Verified by Experts

The correct Answer is:
a
Initial `mEq` of `Cu^(2+)=500xx1.`
Electricity passed `-=(2xx3600)/(96500)=0.746Eq`
`-=746mEq`
`mEq` of `CuCl_(2)` remaining `-=500-74.6=425.4mEq`
`:. N=(425.5)/(500)=0.85`
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