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Ionic strength of a solution made by mix...

Ionic strength of a solution made by mixing equal volumes of `0.01 M NaCl` and `0.02 M AlCl_(3)`

A

`0.065`

B

`0.13`

C

`0.0325`

D

`0.0216`

Text Solution

Verified by Experts

The correct Answer is:
a
After mixing concentraion of `[NaCl]=(0.01)/(2)=0.05`
After mixing concentration of `[AlCl_(3)=(0.02)/(2)=0.01`
`[Na^(o+)]=0.05M,[Al^(3+)]=0.01M,[Cl^(c-)]=0.0035`

`mu=(1)/(2)[0.005(1)^(2)+0.01(3)^(2)+0.35(1)^(2)]=0.065`
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