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DeltaG=DeltaH-TDeltaS and ltBRgt DeltaG...

`DeltaG=DeltaH-TDeltaS` and ltBRgt `DeltaG=DeltaH+T[(d(DeltaG))/(dT)]_(p),` then` ((dE_(cell))/(dT))` is

A

`(DeltaS)/(nF)`

B

`(nE)/(DeltaS)`

C

`-nFE_(cell)`

D

`nFE_(cell)`

Text Solution

Verified by Experts

The correct Answer is:
a
On comparison `:`
`d(DeltaG)//dT=-DeltaS`
`-nF((dE_(cell))/(dT))=-DeltaS`
`:. (dE_(cell))/(dT)=(DeltaS)/(nF)`
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