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During the electrolysis of acidified wa...

During the electrolysis of acidified water, `O_(2)` gas is formed at the anode. To produce `O_(2)` gas at the anode at the rate of `0.224 Ml` per second at `STP`, the current passed is

A

`0.224A`

B

`2.24A`

C

`9.65A`

D

`3.86A`

Text Solution

Verified by Experts

The correct Answer is:
d
From Question above, `0.224 mL O_(2)=3.2xx10^(-4)g`
`I=(W)/(Zt)=(3.2xx10^(-4)xx96500xx4)/(32xx1)=3.86A`
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