The following facts are availabel `:`
`2A^(c-)+B_(2) rarr 2B^(-)+A_(2),`
`2C^(c-)+B_(2) rarr No reaction, `
`2D^(c-)+A_(2) rarr 2A^(c-)+D_(2)`
Which of the following statement is correct ?

Options

A. `E^(c-)._(C^(c-)|C_(2))gtE^(c-)._(B^(c-)|B_(2))gtE^(c-)._(A^(c-)|A_(2))gtE^(c-)._(D^(c-)|D_(2))`
B. `E^(c-)._(C^(c-)|C_(2))ltE^(c-)._(B^(c-)|B_(2))ltE^(c-)._(A^(c-)|A_(2))ltE^(c-)._(D^(c-)|D_(2))`
C. `E^(c-)._(C^(c-)|C_(2))ltE^(c-)._(B^(c-)|B_(2))gtE^(c-)._(A^(c-)|A_(2))gtE^(c-)._(D^(c-)|D_(2))`
D. `E^(c-)._(C^(c-)|C_(2))gtE^(c-)._(B^(c-)|B_(2))ltE^(c-)._(A^(c-)|A_(2))ltE^(c-)._(D^(c-)|D_(2))`

Answer

b

Explanation

Given examples are of non`-` metals. A non`-` metal having higher reduction potential replaces the other from its solution.
Thus, `E^(c-)._(RPD)ltE^(c-)._(RPA)gtE^(c-)._(RPB)` or
Thus, `E^(c-)._(OPD)gtE^(c-)._(OPA)gtE^(c-)._(OPB)`.
Thus , only choice is `(b)` because `E^(c-)._(OPB)ltE^(c-)._(OPC)` as `B` replaces `C` from solution.