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A curent of 3A was passed for 1 hour thr...

A curent of `3A` was passed for 1 hour through an electrolyte solution of `A_(x) B_(y)` in water. If `2.977g ` of `A(` atomic weight `106.4)` was deposited at cathode and `B` was a monovalent ion, the formula of electrolyte was

A

`AB_(2)`

B

`AB`

C

`AB_(3)`

D

`AB_(4)`

Text Solution

Verified by Experts

The correct Answer is:
d
`(W)/(E_(w))=(It)/(96500)(A^(y+)+ye^(_)rarr A)`
`(2.977)/(106.4/y)=(3xx1xx60xx60)/(96500)`
`:.y=4implies` Electrolyte is `AB_(4)`.
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