Home
Class 12
CHEMISTRY
What is E^(c).(red) for the reaction: Cu...

What is `E^(c)._(red)` for the reaction`: Cu^(2+)+2e^(-) rarr Cu` in the half cell `Pt_(S^(2)|CuS|Cu)`. if `E^(c-)._(Cu^(2+)|Cu)` is `0.34V` and `K_(sp)` of `CuS=10^(-35)`?

A

`0.34V`

B

`-0.6925V`

C

`+0.6925V`

D

`-0.66V`

Text Solution

Verified by Experts

The correct Answer is:
b

`E_(S^(2-)|CuS|Cu)=E^(c-)._(Cu^(2+)|Cu)+(0.059)/(2)log K_(sp)CuS`
`=0.34+(0.059)/(2)log10^(-35)=-0.925V`
Promotional Banner

Similar Questions

Explore conceptually related problems

For the cell reaction Zn(s) + Cu^(2+)(aq) rarr Cu(s) + Zn^(2+)(aq) E_("cell")^(@) = 1.10 V, DeltaG^(@) is :

2Cu+O_(2)to2CuO . This reaction is

Heating Cu_2O and Cu_2S will give :

Estimate the E^(c-) reduction for Cu|CuS electrode. Given : K_(sp) of CuS=8.0 xx 10^(-36),E^(c-)._((Cu|Cu^(2+)))=-0.34V

Which of the following reactions occurs at anode in the electrochemical cell reaction ? Zn(s)+Cu^(2+)(aq)toZn^(2+)(aq)+Cu(s)

Complete the following equations: Cu_2O+Cu_2Srarr

Calculate e.m.f. of cell for the reaction : Mg_((s))+Cu^(2+)"(0.0001 M)"rarr Mg^(2+)"(0.001 M)"+Cu_((s)) Given that : E_(Mg^(2+)//Mg)^(@)=-2.37V E_(Cu^(2+)//Cu)^(@)=+0.34V

Give reason: Cu^(2+) is paramagnetic and Cu^(+) is diamagnetic.