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k=4.95xx10^(-5) S cm^(-1) for a 0.001 M ...

`k=4.95xx10^(-5) S cm^(-1)` for a `0.001 M `solution. The reciprocal of the degree of dissociation of acetic acid, if `wedge_(m)^(@)` for acetic acid is `400S cm^(-2) mol^(-1)` is `:`

A

7

B

8

C

9

D

10

Text Solution

Verified by Experts

The correct Answer is:
b
`k=4.95xx10^(-5)S cm^(-1), alpha=(wedge_(m))/(wedge^(@)._(m))`
`wedge_(m)=1000xx(k)/(C)=1000xx(4.95xx10^(-5))/(0.001)=49.5 S cm^(-1)`
`impliesalpha=(49.5)/(400)implies (1)/(alpha)=(400)/(49.5)~~8`
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