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DeltaG for the reaction : (4)/(3) Al+...

`DeltaG` for the reaction `:`
`(4)/(3) Al+O_(2)rarr (2)/(3)Al_(2)O_(3)`
is `-772 kJ mol^(-1)` of `O_(2)`.
Calculate the minimum `EMF` in volts required to carry out an electrolysis of `Al_(2)O_(3)`

Text Solution

Verified by Experts

The correct Answer is:
2
`Alrarr Al^(3+)+3e^(-)`
`(4)/(3) mol of Al=(4)/(3)xx3 mol e^(-) =4 mol e^(-)`
`n=4`
`Delta G=-nFE`
`-772xx1000J =-4xx96500xxE`
`:. E=(772xx1000)/(4xx96500)=2.0V`
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