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13.5 g of Al get deposited when electr...

13.5 g of Al get deposited when electricity is passed through solution of `AlCl_3` . The number of faradays used are

Text Solution

Verified by Experts

The correct Answer is:
`(1.5F)`
`(1.5F)`
`1F=1Eq or Al =(27)/(3)=9g (n ` factor for `Al=3)`
`9g of Alimplies1F`
`13.5 of Al =(1xx13.5)/(9)=1.5F`
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