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On electrolysis of a solution of dilute ...

On electrolysis of a solution of dilute `H_(2)SO_(4)` between platinum electrodes , the gas evolved at the anoe is

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The correct Answer is:
`(O_(2)(g))`
`(O_(2)(g))`
Oxidation potential of `H_(2)Ogt` Oxidation potential of `SO_(4)^(2-)` Hence, oxidation of `H_(2)O` occurs at anode to give `O_(2)(g)`
`H_(2)O rarr 2H^(o+)+2e^(-) +(1)/(2)O_(2)(g)`
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