Home
Class 12
CHEMISTRY
Electrode potential for the electrode M^...

Electrode potential for the electrode `M^(n+)|M` with concerntration is given by the expression under `STP` conditions `:`
`E=E^(c-)+(0.059)/(n)log[M^(n+)]`

Text Solution

Verified by Experts

The correct Answer is:
F
This expression is valid at `298K(` standard condition `)`, not at `273 K (` STP condition `)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

What would be the electrode potential of a silver electrode dipped in a saturated solution of AgCl in contact with 0.1 M KCl solution at 25^(@)C ? E^(c-)._(Ag^(o+)|Ag)=0.799 V K_(sp) of AgCl=1xx10^(-10)

Calculate the electrode potential developed when a silver electrode in dipped in 0.025 M silver nitrate solution at 289K.

The condition for the line L x+m y+n=0 to be a tangent for x^(2)=y is

Calculate the potential of silver electrode in a saturated solution of AgBr(K_(sp)=6xx10^(-13)) containing 0.1 M KB r . E^(c-)._(Ag^(o+)|Ag)=0.80V.

For n,mepsilonN,n|m means that n is a factor of m then relation | is

The hydrogen electrode is dipped in a solution of pH 3 at 25^@C . The potential of the cell would be (2.303 RT//F = 0.059V) :

The e.m.f. of a cell is 1.3 V. The positive electrode has a potential of 0.5 V. The potential of negative electrode is :

What is the potential of a half-cell consisting of zinc electrode in "0.01 M ZnSO_(4) solution 25^(@)C. E^(@) = 0.763 V.