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A solution containing one mole per litre...

A solution containing one mole per litre of each `Cu(NO_(3))_(2), AgNO_(3), Hg_(2)(NO_(3))_(2)` and `Mg(NO_(3))_(2)` is being electrolysed by using electrode potential in volts ( reduction potentials) are `Ag^(+)"|"Ag = + 0.80, Hg_(2)^(2+)"|" Hg = 0.79`.
`Cu^(2+) "|" Cu=0.34" and "Mg^(2+)"|"Mg= - 2.37` V.
With increasing voltage, the sequence of deposition of metal on the cathode will be

A

`Ag,Hg,Cu,Mg`

B

`Mg,Cu,Hg,Ag`

C

`Ag,Hg,Cu,Mg`

D

`Cu,Hg,Ag,Mg`

Text Solution

Verified by Experts

The correct Answer is:
a
Higher the oxidation potential, more easily it is oxidized and faster is the deposition of metal.
Decreasing order of `E^(c-)._(o x I dation)` is `:`
`E^(c-)._(Ag|Ag^(o+)(0.80))gtE^(c-)._(2Hg|Hg_(2)^(2+))(0.79)gtE^(c-)._(Cu|Cu^(2+)(0.34))gtE^(c-)._(Mg|Mg^(2+)(-2.37))`
Hence, the sequence of deposition of metals at the cathode will `Ag, Hg, ` and `Cu`...
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