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Electrolysis of dilute aqueous NaCl solu...

Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`

A

`9.65xx10^(4)s`

B

`19.3xx10^(4)s`

C

`28.95xx10^(4)s`

D

`38.6xx10^(4)s`

Text Solution

Verified by Experts

The correct Answer is:
b
`2H_(2)+e^(-)rarr H_(2)+2overset(c-)(O)H`
For `0.01 mol H_(2),0.02mol ` of electrons are consumed.
Charge required `-0.02xx96500C=Ixxt`
Time required `=(0.02xx96500)/(10xx10^(-3))=19.3xx10^(4)s`
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