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The standard reduction potential for Cu^...

The standard reduction potential for `Cu^(2+)|Cu` is `+0.34V`. Calculate the reduction potential at `pH=14` for the above couple . `K_(sp)` of `Cu(OH)_(2)` is `1.0xx10^(-19)`

Text Solution

Verified by Experts

The correct Answer is:
`-0.22V`
`pH=14,[H^(o+)]=10^(-14),[overset(c-)(O)H]=10^(0)=1`
`Cu(OH)_(2) rarr Cu^(2+)+2overset(c-)(O)H`
`K_(sp)=[Cu^(2+)][overset(c-)(O)H]^(2)`
`1.0xx10^(-19)=[Cu^(2+)][1]^(2),[Cu^(2+)+2e^(-)rarr Cu]`
`[Cu^(2+)]=10^(-19)M`
`E=E^(c-)-(0.0591)/(2)log .(1)/((10^(-19)))`
`=0.34-(0.0591)/(2)xx19`
`=-0.22V`
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