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The rate of reaction is expressed as : ...

The rate of reaction is expressed as :
`(1)/(2)(+d)/(d t)[C] = (1)/(3)(-d)/(d t)[D] = (1)/(4)(+d)/(d t)[A] = -(d)/(d t)[B]`
The reaction is:

A

`(1)/(4)A + (1)/(2)(C ) rarr B+(1)/(3)D`

B

`4A + 2C rarr B + 3D`

C

`B + 3D rarr 4A + 2C`

D

(d) `B + (1)/(3)D rarr (1)/(4)A + (1)/(2)C`

Text Solution

Verified by Experts

The correct Answer is:
C

Rate `= (1)/(2)(d[C])/(d t) = (1)/(3) (-d[D])/(d t) = (1)/(4)(d[A])/(d t) = (-d[B])/(d t)`
`:.` Stoichiometric coefficient of `B = 1`
Stoichiometric coefficient of `D = 3`
Stoichiometric coefficient of `A = 4`
Stoichiometric coefficient of `C = 2`
Therefore, the reaction is : `B + 3D rarr 4A +2C`
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