In the reaction, `2H_(2)O_(2) rarr 2H_(2)O + O_(2)` The rate of decompoistion of `H_(2)O_(2)` is `0.68 kg hr^(-1)`. What is the rate of formation of `O_(2)` and `H_(2)O` in `kg hr^(-1)` ?

Explanation

`(-d[H_(2)O_(2)])/(2 dt) = (d[H_(2)O])/(2 dt) = (d[O_(2)])/(d t)`
(a) `(d[O_(2)])/(dt) = (1)/(2) xx (-d[H_(2)O_(2)])/(dt) xx (Mw of O_(2))/(Mw of H_(2)O_(2))`
`= (1)/(2) xx 0.68 kg hr^(-1) xx (32 xx 10^(-3) kg)/(34 xx 10^(-3) kg)`
`= 0.32 kg hr^(-1)`
(b) `(d[H_(2)O])/(dt) = (2)/(3) xx (-d[H_(2)O_(2)])/(d t) xx (Mw of H_(2)O)/(Mw of H_(2)O_(2)) xx 0.68 kg hr^(-1) xx(18 xx 10^(-3) kg)/(34 xx 10^(-3) kg)`
`= 0.36 kg hr^(-1)`