Home
Class 12
CHEMISTRY
For a chemical reaction A rarr B, it is...

For a chemical reaction `A rarr B`, it is found that the rate of reaction doubles when the concentration of `A` is increased `4` times. What is the order of reaction ? Suggest the rate law also.

Text Solution

Verified by Experts

`r_(1) = k[A]^(n)` …(i)
`r_(2) =2r_(1) = k[4A]^(n)` …(ii)
Divide Eq. (ii) by Eq. (i)
`(2r_(1))/(r_(1)) = (k[4A]^(n))/(k[A]^(n))`
`2 = (4)^(n) rArr (2)^(1) = (2)^(2n) rArr 2n = 1 rArr n = (1)/(2)`
Order of reaction `= (1)/(2) Rate = k[A]^(1)/(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

For the chemical reaction A rarr B it is found that the rate of the reaction doubles when the concentration of A is increased four times . The order in terms of A for this reaction is :

For a reaction : aA rarr bB , the rate of reaction is doubled when the concentration of A is increased by four times. The rate of reaction is equal to

For a reaction : A rarr Products it is found that the rate of reaction increases by a factor of 6.25 when the concentration of A is increased by a factor of 2.5 . The order of the reaction with respect to A is :

For reaction Ararr B the rate of reaction incrases by a factor of 1.857 when the concentration of A is increased by 1.5 times . The order of reaction with respect to A is

For a chemical reaction A+B rarr C it has been found that : (i) rate becomes double when the concentrations of A is doubled (ii) rate becomes 16 times when the concentrations of both A and B are doubled . The rate expression is :