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The rate of a gaseous reaction is given ...

The rate of a gaseous reaction is given by the expresison `k[A]^(2)[B]^(3)`. The volume of the reaction vessel is suddenly reduced to one-half of the initial volume. The reaction rate relative to the original rate will be

A

(a) `1//24`

B

(b) `1//32`

C

( c) `32`

D

(d) `24`

Text Solution

Verified by Experts

The correct Answer is:
C

(c ) Rate `= k[A]^(2)[B]^(3)`
When the volume is halved, the concentration will become double.
`:.` Rate `= k[2A]^(2)[2B]^(3)`
`= 32k[A]^(2)[B]^(3)`
`= 32 xx` Original rate form Eq. (i).
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