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The rate of the reaction 3A + 2B rarr ...

The rate of the reaction
`3A + 2B rarr` Products
is given by the rate expresison: Rate `= k[A][B]^(2)`
If `A` is taken in excess, the order of the reaction would be

A

`3`

B

`2`

C

`1`

D

`5`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) When `A` is taken in excess, its concentration will become constant, the rate law may, therefore, be given as:
Rate `= k[B]^(2) rArr Order = 2`
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