Explain the hybridisation involved is `SF_(6)`.

Explanation

In the formation of `SF_(6)` molecule the central S atom undergoes `sp^(3)d^(2)` hybridization.
Ex: Formation of `SF_(6)` molecule:
Atomic number of Sulphur =16
`:.`Ground state configuration of S
`=1s^(2)2s^(2)2p^(6)3s^(2)3p^(4)`
Excited state 1 configuration
`=1s^(2)2s^(2)2p^(6)3s^(2)2p_(x)^(1)3p_(y)^(1)3p_(z)^(1)3d^(1)`
Excited state II configuration
`=1s^(2)2s^(2)2p^(6)3s^(1)3p_(x)^(1)3p_(y)^(1)3p_(z)^(1)3d_(x^(2)-y^(2))^(1)3d_(z^(2))^(1)`

In the formation of `SF_(6)` molecule the cental S atom under goes `sp^(3)d^(2)` hybridization in its excited state II configuration. As a result of which six hybrid orbitals form on it. All of them contain an electron, each. Now all these six hybrid orbits overlap Head -Head with half filled `2p_(z)` orbitals of six F atoms forming six `sigm` bonds. The shape of the molecule isoctahedral with a bond angle of `90^(@)` and `180^(@)`.