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If `alpha,beta` are the solutions of the equation `acostheta+bsintheta=c, " where "a,b,c inRand " if " a^(2)+b^(2)gt0,cosalphanecosbeta and sin alphane sinbeta` then show that (i) `sinalpha+sinbeta=(2bc)/(a^(2)+b^(2))` (ii) `sinalpha.sinbeta=(c^(2)-a^(2))/(a^(2)+b^(2))`

Text Solution

Verified by Experts

The correct Answer is:
`(c^(2) -a^(2))/(a^(2) +b^(2))`
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