If `theta_(1), theta_(2)` are solutions of the equation a `cos 2theta + bsin 2theta = c, tan theta_(1) != tan theta_(2) and a+c != 0`, then find the values of (i) `tan theta_(1) + tan theta_(2)` (ii) `tan theta_(1).tan theta_(2)`.

Answer

`(i) (2b)/(a+c)` (ii) `(c-a)(a+c)`