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|(a-b-c,2b,2c),(2a,b-c-a,2c),(2a,2b,c-a-...

`|(a-b-c,2b,2c),(2a,b-c-a,2c),(2a,2b,c-a-b)|=`

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The correct Answer is:
`(a+b+c)^(3)= (a+b+c)^(3)`
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