Home
Class 11
MATHS
A particle is moving along a line accord...

A particle is moving along a line according `s= f(t) = 8t + t^3 `. Find the initial velocity

Promotional Banner

Topper's Solved these Questions

  • MOST IMPORTANT QUESTIONS

    VGS PUBLICATION-BRILLIANT|Exercise MEAN VALUE THEOREM (VERY SHORT ANSWER TYPE QUESTIONS)|7 Videos

  • MOST IMPORTANT QUESTIONS

    VGS PUBLICATION-BRILLIANT|Exercise MAXIMA & MINIMA (LONG ANSWER TYPE QUESTIONS)|8 Videos

  • MOST IMPORTANT QUESTIONS

    VGS PUBLICATION-BRILLIANT|Exercise TANGENTS & NORMALS (LONG ANSWER TYPE QUESTIONS)|9 Videos

  • MODEL PAPER 9

    VGS PUBLICATION-BRILLIANT|Exercise SECTION C (Long answer type questions)|7 Videos

Similar Questions

Explore conceptually related problems

A particle is moving along a line according s= f(t) = 8t + t^3 . Find acceleration at t = 2 sec.

A particle is moving along a line according s=f(t)=4t^3-3t^2+5t-1 where s is measured in meters and t is measured in seconds. Find the velocity and acceleration at time t. At what time the acceleration is zero.

A particle moves along a line according to the law s=t^4-5t^2+8 . The intial velocity is

A particle is moving along a straight line according to the law s=16+48t-t^3 . The distance travelled by the particle before coming to rest at an instant is

A particle is moving along a line according to the law s=t^3-3t^2+5 . The acceleration of the particle at the instant where the velocity is zero is

A particle is moving along a line according to s=f(t) =4t^(3)-3t^(2)+5t-1 where s is measured in meter and t is measured in seconds. Find the velocity and acceleration at time t. At what time the acceleration is zero.

A particle moves along a straight line according to the equation s = 8 cos 2t + 4sint. The initial velocity is

A particle moves along a line according to the law s=4t^3-3t^2+2 . At what time will the acceleration be equal to 42 unit/ sec^2 ?