The displacement s of a particle travelling in a straight line in t seconds is given by `s=45t+11t^(2)-t^(3)`. Find the time when the particle comes to rest.

The distance form a fixed point O of a particle pmoving in a straight line from O is given by s=16+48t-t^3 . The direction of motion of the particle after t=4 sec is

If a particle moves alonga straight line by S = 4t^(2) - 8t + 3 and the time at which the particle comes of rest is 't' seconds then '2t' is

At time t, the distance s of a particle moving in a straight line is given by s= 4t^2+ 2t. Find the average velocity between t= 2sec and t= 8 sec.

The displacement of a particle moving in a straight line is given by x=2t^2+t+5 where x is expressed in metre and t in second. The acceleration at t = 2 s is

The distance s feet travelled by a particle in time t seconds is given by s=t^3-6t^2-4t-8 . It's acceleration vanishes at time t =

The displacement of a particle in time 't' is given by S = t^(3) - t^(2) - 8t =18 . The acceleration of the particle when its velocity vanishes is

The distance-time formula for the motion of a particle along a straight line is s=t^(3)-9t^(2)+24t-18 . Find when and where the velocity is zero.

The distance travelled by a pparticle in time 't' is given by S=(2.5m//s^(2))t^(2) . Find the average speed of the particle during the time '0' to '5' sec.

A particle is moving along a straight line according to the law s=16+48t-t^3 . The distance travelled by the particle before coming to rest at an instant is