A wire of length l is cut into two parts which are bent respectively in the form of a square and a circle. What are the lengths of pieces of wire so that the sum of areas is least ?

A wire of length l is cut into two parts which are bent respectively in the form of a square and a circle. What are the lengths of the pieces of the wire respectively so that the sum of the areas is the least.

A wire of length 20cm is cut into two parts which are bent in the form of a square and a circle, then the least value of the sum of areas so formed is

A wire of length 'a' is cut into two parts which are bent in the form a square and a circle. Show that the least value of the sum of the areas so formed is (a^2)/(4(pi+4)) .

A wire of length 'a' is cut into two parts which are bent in the form a square and a circle. Show that the least value of the sum of the areas so formed is (a^(2))/(4(pi + 4)) .

A wire given 'l' is cut into two portions which are bent into the shapes of a circle and a square respectively . If the sum of the areas of the circle and square will be least when side of square is lambda then 8lambda =

A piece of wire 8m in length is cut into two pieces and each piece is bent into a squares. Where should the cut in the wire be made if the sum of the areas of these squares is to be 2 m^(2) ?