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Find the pole of x + y + 2= 0 with resp...

Find the pole of `x + y + 2= 0 ` with respect
to the circle
`x^(2)+ y^(2) - 4x + 6y -12= 0`.

Text Solution

Verified by Experts

The correct Answer is:
(-23,-28)
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Knowledge Check

  • The normal to a circle S =0 at P (1,3) is x + 2y -7 and it has another normal at Q(3,5) which is the polar of the point A(7, -(1)/(2)) with respect to the circle x ^(2) + y ^(2)- 4x + 6y -12 =0. Then the equation of the circle S =0 is

    A
    `x ^(2) + y ^(2) -10x -2y + 6=0`
    B
    `x ^(2) + y ^(2) - 5x -2y + 1=0`
    C
    `x ^(2) + y ^(2) - 8x + 2y -8=0`
    D
    `x ^(2) + y ^(2) -7x + 3y -12=0`
  • Similar Questions

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    Find the coordinates of the pole of the straight line (i) x+y+2=0 with respect to the circle x^(2)+y^(2)-4x+6y+2=0 (ii) 3x+4y-45=0 with respect to the circle x^(2)+y^(2)-6x-8y+5=0 (iii) x-2y+22=0 with respect to the circle x^(2)+y^(2)-5x+8y+6=0 (iv) ax+by+c=0 with respect to the circle x^(2)+y^(2)=r^(2)

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