Home
Class 12
MATHS
Find the equation of tangent to y^(2) = ...

Find the equation of tangent to `y^(2) = 16x` inclined at an angle `60^(@)` with its axis also find its point of contact.

Text Solution

Verified by Experts

The correct Answer is:
`0`
Promotional Banner

Topper's Solved these Questions

  • MODEL PAPER 7

    VGS PUBLICATION-BRILLIANT|Exercise SECTION - B (SHORT ANSWER TYPE QUESTIONS)|7 Videos

  • MODEL PAPER 7

    VGS PUBLICATION-BRILLIANT|Exercise SECTION - C (LONG ANSWER TYPE QUESTIONS)|7 Videos

  • MODEL PAPER 7

    VGS PUBLICATION-BRILLIANT|Exercise SECTION-C (LONG ANSWER TYPE QUESTIONS)|7 Videos

  • MODEL PAPER 6

    VGS PUBLICATION-BRILLIANT|Exercise SECTION-C|7 Videos

  • MODEL PAPER 8

    VGS PUBLICATION-BRILLIANT|Exercise SECTION - C (LONG ANSWER TYPE QUESTIONS)|7 Videos

Similar Questions

Explore conceptually related problems

The equation of the tangent to the parabola y^(2)=8x inclined at 30^(@) to the x axis is

The equation of the tangent to the circle x^(2)+y^(2)=16 which are inclined at an angle of 60^(@) to the x-axis is

The tangent to y^(2)=ax makes an angle 45^(@) with x-axis . Then its point of contact is

Equation of the tangent to the circle x^(2)+y^(2)=3 , which is inclined at 60^(@) with the x-axis is

Find the equation of the tangents to the circle x^(2)+y^(2)-4x-5y+3=0 which are inclined at 45^(@) with X axis.

Find the equation of the tangents to the circle x^(2) + y^(2) -4x - 6y + 3 = 0 which makes an angle 45^(@) with X - axis.