xyz6

Find the number of terms in 4xyz-(3)/(x^(2))+6xyz^(2)-5z^(3)+6x:

If x+y+z=0, then,x^(3)+y^(3)+z^(3)+3backslash xyz is equal to (a) 0 (b) 6xyz(c)12xyz(d)xyz

Add: (i) 3x, 7x (ii) 7y, -9y (iii) 2xy, 5xy, -xy (iv) 3x, 2y (v) 2x^(2), -3x^(2), 7x^(2) (vi) 7xyz, -5xyz, 9xyz, - 8xyz (vii) 6a^(3) , - 4a^(3), 10 a^(3), - 8a^(3) (viii) x^(2) - a^(2), -5x^(2) + 2a^(2), -4x^(2) + 4a^(2)

If x,y,z are real and 4x^(2)+9y^(2)+16z^(2)=2xyz{(6)/(x)+(4)/(y)+(3)/(z)}

Find the products ((4)/(3)x^(2)yz) xx((1)/(3)y^(2)zx) xx(-6xyz^(2))

lf x+y+ z= 6, xyz=-10 and x^2 + y^2 +z^2 = 30 , then what is the value of (x^3 + y^3 + z^3) ?

If x+y+z=6, xyz=-10 and x^2+y^2+z^2=30 , then what is the value of (x^3+y^3+z^3) ? यदि x+y+z=6, xyz=-10 और x^2+y^2+z^2=30 है, तो (x^3+y^3+z^3) का मान क्या होगा ?

If x+y+z=6, xyz=-10 and x^2+y^2 +z^2 =30 , then what is the value of (x^3+y^3+z^3) ? यदि x+y+z=6, xyz=-10 तथा x^2+y^2 +z^2 =30 है, तो (x^3+y^3+z^3) का मान क्या होगा?

The system of equations 3x+y+2z=6,xyz=-5,3xy+2yz+6xz=-1 has a solution (x,y,z), where x,y,z are integers.Then the value of (x+z)/(y) is equal to (i)0(ii)1(iii)2(iv)3